Free · Year 1 of high school · 50 minutes · 15 questions · no penalty

Practice mixed test — Year 1: the whole first term.

15 questions drawn at random from a bank of 25, on the block of the programme your teacher is finishing: every attempt is a different test. No penalty for wrong answers, so answer even if you are not sure. At the end you receive by email the correct answer to every question and your weak topics — with an account you see them straight away here on the page. The step-by-step solution unlocks with your first lesson.

A class test is the written test an Italian high-school class sits after each block of the programme; this practice version is multiple choice.

Test in ItalianThe questions of this simulator are in Italian, as in the real exam.

Test prepared by Gaetano Livornese · Aerospace engineer, Politecnico di Milano · maths and physics tutor · updated 13 October 2026

Programme covered by the test

Fractions, proportions and percentages
Powers and the rules for exponents
Scientific notation and orders of magnitude
HCF, LCM and prime factorisation
Sets and basic logic
Monomials: operations and degree
Polynomials and the first special products

Two worked examples from the test

Question 1 · Verifica mista — 1ª superiore · Insiemi e logica

Dati gli insiemi $A = {1, 2, 3, 4}$ e $B = {3, 4, 5}$ , quanti elementi ha $A \cup B$ ?

A $4$
B $5$ correct answer
C $2$
D $7$

Solution

Passo 1 — Che cos'è l'unione. $A \cup B$ contiene tutti gli elementi che stanno in $A$ oppure in $B$ .

Passo 2 — Elenco gli elementi.

$A \cup B = {1, 2, 3, 4, 5}$

Passo 3 — Conto. Gli elementi sono $5$ : il $3$ e il $4$ appartengono a entrambi gli insiemi ma si scrivono una volta sola.

Errore tipico: il $7$ si ottiene sommando $4 + 3$ (cioè contando due volte gli elementi comuni), il $2$ è invece il numero di elementi di $A \cap B$ .

Question 2 · Verifica mista — 1ª superiore · Frazioni e percentuali

Risolvi la proporzione nell'incognita $x$ :

$(x + 1) : 8 = 9 : 6$

A $x = 12$
B $x = \frac{13}{3}$
C $x = 11$ correct answer
D $x = \frac{16}{3}$

Solution

In una proporzione il prodotto dei medi è uguale al prodotto degli estremi.
Medi: $8$ e $9$ . Estremi: $x + 1$ e $6$ .
Quindi $6 (x + 1) = 8 \cdot 9 = 72$ , cioè $x + 1 = 12$ .
Perciò $x = 11$ .
Errore tipico: dimenticare il $- 1$ finale e rispondere $x = 12$ .

In the online practice test you will find 13 more questions like these; the correct answer to every question arrives by email.

Prefer paper? Download the test as a PDF (15 questions, 4 pages · 82 KB, ready to print). You receive the solutions by email after taking it online.

Download the PDF

What a maths test on mixed test looks like

An end-of-term test that draws on the whole programme so far: expressions with fractions and powers, scientific notation, HCF and LCM, sets and the first special products. No topic in depth, but none can be left behind.

The mistake that costs the grade

Studying only the last topic. In a mixed test the marks are lost on the things from October that seemed filed away — above all the rules for powers and the signs in algebra — not on the ones just explained.

How to use this practice test

Take it once cold, without revising and with the timer on: it is there to show you where you stand, not to look good. Then look at your weak topics, revise only those — usually two or three, not the whole chapter — and retake it after a few days. The 15 questions are drawn from a bank of 25, so the second attempt is not the same test and the scores are genuinely comparable.

Is the score not enough?

See which topics lost you the most marks, then read how to handle test anxiety — or we look at your results together: the diagnostic is free.

Book the free diagnostic call The other Year 1 tests